Test Run at Yale December 2002.

Question: If excited projectiles are allowed to leave the target,
          what is the attenuation effect on the angular distribution
          of the de-exciting Gamma rays?

Setup:    2 Ge detectors (1 & 4) at backwards angles
          Q2 = 0.97   Q4 = 0.91 for this run
          2 NaI (2 & 3) at forward angles
          Q2 = 0.92   Q4 = 0.76


1.  Measurement of Anisotropy with a 'normal' target where all excited
    projectiles are stopped, only the beam passes through the target.

    130-Te beam at 280 MeV on target

    T1:[0.4 mg/cm^2 C | 3.72 mg/cm^2 Gd | 7.36mg/cm^2 Cu] 
       plus a beam stop of 11.4 mg.cm^2 Cu

	Det     cnts       err  

	1     1025.0       34.2  (runs 1 to 4)
	1      373.0       21.1
	4      730.0       29.2
	4      270.0       18.3

	ratio 1/4 = 2.725757 0.139701

    Anisotropy( 50.0/ 80.0) =  2.726(0.138)     ETA = 0.02437(0.00172)

     A(align)_2  =  0.6929     A(exp)_2  =  0.5916(0.0071)
     A(align)_4  = -1.5600     A(exp)_4  = -0.7998(0.0536)
     At 67.5 deg the slope = -2.2528(0.1062)


	Det     cnts       err  

	2     4288.0       71.9  (only runs 1 and 2)
	2     1422.0       45.4
	3     4422.0       73.9
	3     1759.0       61.5

	ratio 2/3 = 2.753303 0.072874

    Anisotropy( 50.0/ 80.0) =  2.753(0.073)     ETA = 0.01850(0.00106)

     A(align)_2  =  0.6571     A(exp)_2  =  0.5842(0.0042)
     A(align)_4  = -1.3029     A(exp)_4  = -0.8208(0.0275)
     At 67.5 deg the slope = -2.2749(0.0557)

    The average correlation coefficients:

     A(theo)_2 =  0.7143     A(exp)_2  =  0.5861(0.0036)
     A(theo)_4 = -1.7143     A(exp)_4  = -0.8164(0.0245)
     At 67.5 deg the slope = -2.2701(0.0493)













2.  Measurement of Anisotropy with a 'special' target where the excited
    projectiles are not stopped and escape into vacuum.

    T2:[0.4 mg/cm^2 C | 5.68 mg/cm^2 Cu] 
       plus a beam stop of 11.4 mg.cm^2 Cu 3 mm after the target.

    Average escape velocity is 2.77 vo
    Average decay velocity  is 3.8  vo (from spectra)


	Det     cnts       err
  
	1      636.0       27.6
	1      269.0       17.9
	4      444.0       22.4
	4      232.0       17.8

	ratio 1/4 = 2.127159 0.129141

    Anisotropy( 50.0/ 80.0) =  2.127(0.129)     ETA = 0.03326(0.00219)

     A(align)_2  =  0.6929     A(exp)_2  =  0.5546(0.0091)
     A(align)_4  = -1.5771     A(exp)_4  = -0.5279(0.0690)


	Det     cnts       err

	2     4095.0       73.8
	2     2235.0       60.8
	3     5174.0       81.3
	3     2082.0       55.4

	ratio 2/3 = 2.133836 0.047949

    Anisotropy( 50.0/ 80.0) =  2.134(0.048)     ETA = 0.02908(0.00096)

     A(align)_2  =  0.6571     A(exp)_2  =  0.5425(0.0038)
     A(align)_4  = -1.3029     A(exp)_4  = -0.5452(0.0251)

    The average correlation coefficients:

     A(theo)_2 =  0.7143     A(exp)_2  =  0.5443(0.0035)
     A(theo)_4 = -1.7143     A(exp)_4  = -0.5430(0.0236)

	At 67.5 deg. the slope = -1.7124(0.0519)





















3.  Measurement of Anisotropy with a Fe target where the excited
    projectiles are stopped (like measurement 1)

    T3:[0.06 mg/cm^2 C | 7.1 mg/cm^2 Fe] 
       plus a beam stop of 5.7 mg.cm^2.

	Det     cnts       err
  
	1      156.0       13.2
	1       45.0        7.7
	4      118.0       11.8
	4       37.0        8.5

	ratio 1/4 = 3.325035 0.523665


	Det     cnts       err
  
	2     1220.0       40.2
	2      418.0       28.3
	3     1162.0       40.2
	3      527.0       29.4

	ratio 2/3 = 2.536819 0.126705